*5.41 (Occurrence of max numbers) Write a program that reads integers, finds the larg-
est of them, and counts its occurrences. Assume that the input ends with number
0. Suppose that you entered 3 5 2 5 5 5 0; the program finds that the largest
is 5 and the occurrence count for 5 is 4.
(Hint: Maintain two variables, max and count. max stores the current max num-
ber, and count stores its occurrences. Initially, assign the first number to max
and 1 to count. Compare each subsequent number with max. If the number is
greater than max, assign it to max and reset count to 1. If the number is equal to
max, increment count by 1.)

Enter numbers: 3 5 2 5 5 5 0

The largest number is 5

The occurrence count of the largest number is 4

Enter numbers: 3 5 2 5 5 5 0

The largest number is 5

The occurrence count of the largest number is 4

import java.util.Scanner; public class ProgrammingEx5_41 { public static void main(String[] args) { Scanner input = new Scanner(System.in); // Enter saving amount System.out.print("Enter Numbers:"); int i; int max = 0; int count = 0; while ((i = input.nextInt()) != 0) { if (i > max) { max = i; count = 1; } else if (i == max) { count++; } } System.out.println("The largest number is " + max); System.out.println("The occurrence count of the largest number is " + count); } }

THANK YOU SO MUCH

ReplyDeleteyou are welcome

ReplyDelete