*8.13 (Locate the largest element) Write the following method that returns the location of the largest element in a two-dimensional array. public static int[] locateLargest(double[][] a) The return value is a one-dimensional array that contains two elements. These two elements indicate the row and column indices of the largest element in the two-dimensional array. Write a test program that prompts the user to enter a two- dimensional array and displays the location of the largest element in the array.
Here is a sample run:
Enter the number of rows and columns of the array: 3 4
Enter the array:
23.5 35 2 10
4.5 3 45 3.5
35 44 5.5 9.6
The location of the largest element is at (1, 2)
Here is a sample run:
Enter the number of rows and columns of the array: 3 4
Enter the array:
23.5 35 2 10
4.5 3 45 3.5
35 44 5.5 9.6
The location of the largest element is at (1, 2)
import java.util.Scanner; public class ProgrammingEx8_13 { public static void main(String[] args) { java.util.Scanner input = new Scanner(System.in); System.out .print("Enter the number of rows and columns of the array:"); int i = input.nextInt(); int j = input.nextInt(); int[] intResult; System.out.println("Enter the array:"); double[][] in = new double[i][j]; for (int k = 0; k < i; k++) { for (int k2 = 0; k2 < j; k2++) { in[k][k2] = input.nextDouble(); } } intResult = locateLargest(in); System.out.println("The location of the largest element is at (" + intResult[0] + ", " + intResult[1] + ")"); } public static int[] locateLargest(double[][] a) { double dblMax = 0; int[] intReturn = new int[2]; for (int k = 0; k < a.length; k++) { for (int k2 = 0; k2 < a[k].length; k2++) { if (a[k][k2] > dblMax) { dblMax = a[k][k2]; intReturn[0] = k; intReturn[1] = k2; } } } return intReturn; } }
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