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Wednesday, 18 January 2017

Chapter 22 Exercise 2, Introduction to Java Programming, Tenth Edition Y. Daniel LiangY.

22.2 (Maximum increasingly ordered subsequence) Write a program that prompts the user to enter a string and displays the maximum increasingly ordered subsequence of characters. Analyze the time complexity of your program.


import java.util.*;

public class Exercise_22_02 {
 public static void main(String[] args) {
  // Create a Scanner
  Scanner input = new Scanner(System.in);

  // Prompt the user to enter a string
  System.out.print("Enter a string: ");
  String string = input.nextLine(); 

  LinkedList<Character> max = new LinkedList<>();

  // Find the maximum increasingly ordered subsequence
  for (int i = 0; i < string.length(); i++) { 
   LinkedList<Character> list = new LinkedList<>();
   list.add(string.charAt(i));
   for (int j = i + 1; j < string.length(); j++) {
    if (string.charAt(j) > list.getLast()) {
     list.add(string.charAt(j)); 
    }
   }

   if (list.size() > max.size()) {
    max.clear();
    max.addAll(list);
   }
   list.clear();
  }

  // Display the maximum consecutive 
  // increasingly ordered substring
  for (Character ch: max) { // single loop
   System.out.print(ch); // Simple statement
  }
  System.out.println();
 }

/*********************************************************************************
*  Analyze the time complexity of your program:                             *  
*  1 outerloop = n;                                                         *
*  1 innerloop = n - 1;                                                     *
*  1 simple statement = 1                                                        *
*  1 single loop * 1 simple statement = 1;                                  * 
*  T(n) = (n * (n - 1)) + (1 + 1);                                               *  
*  T(n) = O(n^2) + O(n);                                                         *  
*  T(n) = O(n^2) Quadratic time;                                            * 
*********************************************************************************/ 
}

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