Saturday 11 June 2016

Chapter 3 Exercise 24, Introduction to Java Programming, Tenth Edition Y. Daniel LiangY.

**3.24 (Game: pick a card) Write a program that simulates picking a card from a deck of 52 cards. Your program should display the rank (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King) and suit (Clubs, Diamonds, Hearts, Spades) of the card. Here is a sample run of the program:
The card you picked is Jack of Hearts




public class ProgrammingEx3_24 {
 public static void main(String[] args) {
 
  int card = (int) (Math.random() * 52.0); // pick a card 0-51
  int rank = card / 4; // determine the rank 0-12
  int suit = card % 4; // determine the suit 0-3
  String strRank = "";
  String strSuit = "";
 
  switch (rank) {
  case 0:
   strRank = "Ace";
   break;
  case 10:
   strRank = "Jack";
   break;
  case 11:
   strRank = "Queen";
   break;
  case 12:
   strRank = "King";
   break;
  default:
   strRank = "" + (rank + 1);
   break;
  }
 
  switch (suit) {
  case 0:
   strSuit = "Clubs";
   break;
  case 1:
   strSuit = "Diamonds";
   break;
  case 2:
   strSuit = "Hearts";
   break;
  case 3:
   strSuit = "Spades";
   break;
  }
   
  System.out.print("The card you picked is " + strRank +" of " + strSuit );
 }
 
}

1 comment :

  1. another solution by Y. Daniel LiangY
    final int NUMBER_OF_CARDS = 52;
    // Pick a card
    int number = (int)(Math.random() * NUMBER_OF_CARDS);
    System.out.print("The card you picked is ");
    if (number % 13 == 0)
    System.out.print("Ace of ");
    else if (number % 13 == 10)
    System.out.print("Jack of ");
    else if (number % 13 == 11)
    System.out.print("Queen of ");
    else if (number % 13 == 12)
    System.out.print("King of ");
    else
    System.out.print((number % 13) + " of ");

    if (number / 13 == 0)
    System.out.println("Clubs");
    else if (number / 13 == 1)
    System.out.println("Diamonds");
    else if (number / 13 == 2)
    System.out.println("Hearts");
    else if (number / 13 == 3)
    System.out.println("Spades");

    ReplyDelete